Hi,
	The long real format is:

	Bit 63: sign
	bit 52-62: exponent
	Bit 0-51: mantissa

	For short and long reals the mantissa is always assumed to be in
the range 1.0 <= m < 2.0.  (We're ignoring denormalized numbers).  Since the
first bit of the mantissa is always 1 it is not stored and is implicit in
the mantissa.

	Starting with the number -26.59375, the first thing to do is take
out the sign.  It is negative so bit 63 is a one.  Then we have 26.59375.
The next thing to do is to normalize into the range 1.0 <=m < 2.0; this
will also get us the exponent.  In this case we divide by 2 to the 4th power,
or 16 and get: 1.662109375.  The exponent must be biased by 1023 for long
reals so we have an exponent of 1027.

We discard the 1 since this is long real and get .662109375.  Then
we start subtracting out negative powers of two:

	  0.662109375
	- 0.5		(2 to the -1)
	  0.162109375
	- 0.125		(2 to the -3)
	  0.037109375
	- 0.03125	(2 to the -5)
	  0.005859375
	- 0.00390625	(2 to the - 8)
	  0.001853125
	- 0.00097655	(2 to the - 10)
	  0.000876575
	- 0.000478275	( 2 to the -11)
	  0.000398300
	- 0.0002382875  ( 2 to the - 12)
	  0.0001600125


You'd go on like that until you got all 51 bits of the mantissa.
Putting the digits together we get:

101010010111... so the answer is (approximately)


110000000011101010010111... (Filled out to 64 digits)

Have fun,

David